retroforth/example/advent-of-code-2021-day-1.retro
crc bbc34d7962 new example: 2021 advent of code, day 1
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2021-12-01 13:09:55 +00:00

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Forth

# Part 1
This is a pretty easy problem.
Using the `file:for-each-line` to iterate over each line,
I increment a variable for each increase. I also leave the
most recently read value on the stack for the next comparison.
The variable is initialized to -1. My initial comparison
value is 0, so the first data from the file will be greater
than this. Using an initial -1 value ensures that the needed
adjustment is factored in.
~~~
#-1 'Increased var-n
:process (ns-n) s:to-number tuck lt? [ &Increased v:inc ] if ;
#0 'day1.input [ process ] file:for-each-line drop
@Increased n:put nl
~~~
# Part 2
The introduction of a three value sliding window makes this
a little trickier. I chose to use only a single accumulator
variable, keeping the values for the window and the latest
sum on the stack.
I use `reorder` to update the stack orderings when adjusting
the values for the sliding window and when moving the newest
sum to the bottom.
I'm using the same trick with a negative starting value
(-3 in this case) for my count, to allow for the initial
non-existant entries of zero.
~~~
#-3 'Increased var-n
:slide 'abcde 'cdeacde reorder ;
:sum + + ;
:check [ lt? [ &Increased v:inc ] if ] sip ;
:update 'abcd 'dabc reorder ;
:process s:to-number slide sum check update ;
#0 #0 #0 #0 'day1.input [ process ] file:for-each-line
drop-pair drop-pair
@Increased n:put nl
~~~