bbc34d7962
FossilOrigin-Name: a5eb1751ff240899d19ba07df45515d80fefe35c7055b41d3a6c65d3782115d9
52 lines
1.4 KiB
Forth
52 lines
1.4 KiB
Forth
# Part 1
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This is a pretty easy problem.
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Using the `file:for-each-line` to iterate over each line,
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I increment a variable for each increase. I also leave the
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most recently read value on the stack for the next comparison.
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The variable is initialized to -1. My initial comparison
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value is 0, so the first data from the file will be greater
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than this. Using an initial -1 value ensures that the needed
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adjustment is factored in.
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~~~
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#-1 'Increased var-n
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:process (ns-n) s:to-number tuck lt? [ &Increased v:inc ] if ;
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#0 'day1.input [ process ] file:for-each-line drop
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@Increased n:put nl
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~~~
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# Part 2
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The introduction of a three value sliding window makes this
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a little trickier. I chose to use only a single accumulator
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variable, keeping the values for the window and the latest
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sum on the stack.
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I use `reorder` to update the stack orderings when adjusting
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the values for the sliding window and when moving the newest
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sum to the bottom.
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I'm using the same trick with a negative starting value
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(-3 in this case) for my count, to allow for the initial
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non-existant entries of zero.
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~~~
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#-3 'Increased var-n
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:slide 'abcde 'cdeacde reorder ;
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:sum + + ;
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:check [ lt? [ &Increased v:inc ] if ] sip ;
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:update 'abcd 'dabc reorder ;
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:process s:to-number slide sum check update ;
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#0 #0 #0 #0 'day1.input [ process ] file:for-each-line
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drop-pair drop-pair
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@Increased n:put nl
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~~~
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